Section 23 Applications of étale comparison
Reference.
In this section, we describe some applications of the étale comparison theorem for prismatic cohomology (Theorem 22.6.1).
Subsection 23.1 Tilting of valuation rings
We prove the converse of Lemma 22.4.4 and recover the tilting correspondence for perfectoid fields (Theorem 8.3.4). This theme will be continued in the treatment of almost purity (Section 25).
Proof.
By Lemma 22.4.2, is a valuation ring if and only if is; it thus remains to show that if is AIC, then so is So suppose by way of contradiction that is not AIC. By Lemma 22.4.3, and have the same (algebraically closed) residue field and the same (divisible) value group. Consequently, any nontrivial finite Galois extension of is totally wildly ramified and so has Galois group which is a -group. This in turn implies that admits a nontrivial -extension, and so However, this contradicts Theorem 22.6.1: the right-hand side of (22.1) vanishes by Proposition 22.1.1.
Remark 23.1.2.
Theorem 23.1.1 can be used to recover the tilting correspondence for perfectoid fields (Theorem 8.3.4) as follows. Let be a perfectoid field and let be a completed algebraic closure of Theorem 23.1.1 implies that is an algebraically closed extension of so it contains a completed algebraic closure of Each finite subextension of over untilts to a finite extension of within which is perfectoid. The completed union of these extensions is an untilt of so by Lemma 22.4.4 this untilt is algebraically closed. In particular it contains the integral closure of in and so by completeness it equals in other words,
Now let be an irreducible polynomial with roots By the previous paragraph, we can find a finite Galois perfectoid extension of within and an element such that for By Krasner’s lemma, we have it follows that every finite extension of within is contained in a finite Galois perfectoid extension of within Using the Galois correspondence, we deduce that every finite extension of is the untilt of some finite extension of within and so is perfectoid.
This argument is essentially the proof of Theorem 8.3.4 given in [80], Theorem 1.5.6 except that therein, Theorem 23.1.1 is proved by an explicit computation ([80], Lemma 1.5.4). The novelty here is that arc-descent allows us to deduce this from the much more basic statement that can be extended to an AIC valuation ring, which is then automatically a lens (Lemma 22.4.1).
Subsection 23.2 Torsion in étale and de Rham cohomology
Lemma 23.2.1.
Let be a valuation ring with fraction field and residue field Then for any matrix over the rank of as a matrix over is greater than or equal to the rank of as a matrix over
Proof.
Let be the rank of as a matrix over Then there exists an submatrix of whose determinant has nonzero image in This determinant also has nonzero image in and so the rank of as a matrix over is at least
Lemma 23.2.2. Semicontinuity for perfect complexes.
Let be a valuation ring with fraction field and residue field Let be a perfect complex in Then for each
Remark 23.2.3.
A minimal example of strict inequality in Lemma 23.2.2 is a two-term complex placed in degrees 0 and 1, where is a nonzero element of the maximal ideal: over the cohomology vanishes, but over we have a nonzero
Proof.
We may assume that is represented by a bounded complex of finite free -modules. Fix bases of these modules and let be the matrices representing the differentials in and out of degree in these bases. By Lemma 23.2.1, the rank of does not increase when passing from to and the corank of does not decrease; combining these two points yields the desired inequality. (Compare [117], tag 0BDI.)
Lemma 23.2.4.
Let be an algebraically closed field of characteristic Let be a pair in which is perfect as a complex of -modules. Then for each integer the natural map
Proof.
Exercise (Lemma 23.2.4).
The following statement recovers Theorem 1.2.2.
Theorem 23.2.5.
Let be a complete algebraically closed extension of the field Let be the valuation ring of and let be the residue field of Let be a smooth proper formal scheme over with generic fiber and special fiber Then for all
Proof.
By Lemma 22.4.1, is a lens; let be its underlying perfect prism, choose a generator of (Theorem 7.2.2), and put Let be the perfect crystalline prism corresponding to By Theorem 7.3.5, the morphism lifts to a unique morphism
We conflate the underlying spaces of the formal scheme and the ordinary scheme on this space, we may define prismatic cohomology complexes of sheaves and By the Hodge-Tate comparison (Theorem 12.4.1) and its compatibility with base change (Lemma 15.1.3), we have
(with the completion being -adic).
Define
Since preserves limits, is a derived -complete object of By the Hodge-Tate comparison and the usual finiteness property of coherent cohomology on a proper scheme ([117], tag 02O5), is a perfect complex of -modules. By derived Nakayama (Proposition 6.6.2) applied to suitable truncations, we deduce that is a perfect complex of -modules.
Reduce modulo (which gets rid of the completion) and applying the crystalline comparison theorem (Corollary 14.4.10) yields
Since is perfect, the Frobenius twist has no effect on -dimensions; we thus deduce the desired equality.
(in fact equality will hold as perf [18], Lecture IX, Remark 5.3, but this will suffice for now). Apply the étale comparison theorem (Theorem 22.6.1) to the terms of an open affine cover of to obtain an identification
then apply Lemma 23.2.4 to obtain for each an injective linear map
This yields the desired inequality. (Compare [18], Lecture IX, Theorem 5.1.)
Subsection 23.3 Tate twists
Definition 23.3.1.
For any scheme and any positive integer let be the sheaf on for the flat topology which is the kernel of the multiplication-by- map on (If is invertible on we may use instead the étale topology.) Define the pro-sheaf
For define the presheaf on the category of lenses, valued in by the following formula: for a perfect prism with slice let be a generator of and set
with the first term placed in degree (Note that the resulting object does not depend on the choice of ) By Theorem 22.5.2, this construction defines an arc -sheaf.
Lemma 23.3.2.
Proof.
By arc -descent and Example 20.3.8, we may reduce to the case where is a product of -complete AIC valuation rings, and then to the case of a single such ring. In this case, the map is surjective modulo (by the AIC property) and hence surjective by derived Nakayama (Proposition 6.3.1).
Suppose that is of characteristic In this case, we may take and then The map on is visibly injective, so both sides of the desired isomorphism are zero.
Suppose next that is of characteristic Choose a morphism let be the element and put We can then take the generator of to be we may then identify with This gives the desired natural isomorphism
To specify a natural isomorphism it now suffices to do so for In this case, we must check that the action of on matches the action on this follows from the fact that
Remark 23.3.3.
One can promote Lemma 23.3.2 to the assertion that the two definitions of Tate twists correspond to a single construction on the quasisyntomic site, as per [23], section 7.4. We will not spell this out further here; instead, see [25], section 14.
Theorem 23.3.4.
Let be a lens.
- We have a canonical identification
- For
we have a canonical identification
Proof.
Exercises 23.4 Exercises
1.
Prove Lemma 23.2.4.