Section 14 Hodge-Tate comparison for crystalline prisms
Reference.
In this section, we prove the Hodge-Tate comparison theorem (Theorem 12.4.1) in the special case where the base prism is crystalline (meaning that ) and the ring is a polynomial ring over This simultaneously shows off some key ideas and provides a crucial base case for the general argument.
Subsection 14.1 de Rham cohomology in characteristic
We first recall how de Rham cohomology works in characteristic focusing on the key case of an affine space (polynomial ring). The key point is that even in this case the cohomology is quite large, and in fact the cohomology groups reflect the structure of the original complex via the Cartier isomorphism.
Proof.
For any we have
because in This proves the claim for from which the rest follows at once.
Definition 14.1.2.
For a morphism in the map factors through an -linear map where We call the relative Frobenius for the map
In geometric language, is the linearization of over obtained by factoring through a fiber product. See Figure 14.1.3.
Corollary 14.1.4.
Proof.
It suffices to check the claim for Moreover, we may assume as we may then take colimits to deduce the case where is a polynomial ring in any number of variables, and then take quotients to deduce the case where is arbitrary.
When we may identify with a second copy of with the map being given by the -linear substitution In particular, as per Lemma 14.1.1.
Remark 14.1.5.
As indicated in Figure 14.1.3, the construction of relative Frobenius extends to an arbitrary morphism of schemes in characteristic The example of a polynomial ring, and its description in the proof of Corollary 14.1.4, may be misleading: in general and will not be isomorphic over For example, if is the spectrum of an algebraically closed field and is an elliptic curve over then the -invariants and will differ in general (the latter being the image of the former under ).
Lemma 14.1.6. Cartier isomorphism for affine space.
Proof.
The map induces a morphism of complexes thanks to Corollary 14.1.4. To check that this map is a quasi-isomorphism, we form a decomposition
We obtain a morphism of complexes (not respecting the multiplicative structure) taking to for
We must show that the composition of these maps is homotopic to the identity on By proceeding by induction, we may reduce to the case In this case, for maps to taking to and this map is evidently invertible.
Remark 14.1.7.
While the Cartier map described in Lemma 14.1.6 is defined in terms of coordinates on the polynomial ring the construction is canonical up to homotopy in that the resulting map in is well-defined independently of the way that is expresesd as a polynomial ring. For example, making the change of variables does not change the map because
Yet another construction can be given (for then deducing the general case by base change) by lifting from to Given an element lifting the element reduces to an element of independent of the choice of and this is the image of under the Cartier map.
This last construction is quite similar to how the Cartier isomorphism will appear in the proof of the Hodge-Tate comparison for crystalline prisms (Proposition 14.4.12). In fact that result will itself establish the canonicality of the Cartier isomorphism, so we don’t need to worry much about it right now.
In any case, once canonicality is established by some means, we can easily promote Lemma 14.1.6 to a similar statement for any smooth morphism in We omit the details here, as we will see the same argument again soon (Lemma 15.1.2).
Subsection 14.2 Divided powers
We next recall an algebraic construction that will help us study de Rham cohomology in mixed characteristic. See [15], section 3 for a detailed development, which also covers cases where the ring can have -torsion.
Definition 14.2.1.
From the identities
we see that the set of for which for all is an ideal of For an ideal contained in this ideal, we say that admits divided powers on
Example 14.2.2.
Remark 14.2.3.
Our definition of “admits divided powers” is not quite the usual one: normally one also requires that maps into for each For example, this occurs in Example 14.2.2 because (14.2) includes rather than However, the last statement in Definition 14.2.4 ensures that this discrepancy doesn’t affect anything later.
Definition 14.2.4.
and the fact that (it counts unordered partitions of into -element subsets), we see that admits divided powers on the ideal generated by for all (even in the stronger sense of Remark 14.2.3).
Remark 14.2.5.
When studying divided powers, it is common to use the initialism pd for the French phrase puissances divisées. For example, the divided power envelope is also called the pd-envelope.
One key motivation for introducing divided powers is to formulate the Poincaré lemma.
Proposition 14.2.6.
Proof.
Exercise (see Exercises 14.5).
Remark 14.2.7.
Proposition 14.2.6 amounts to the computation of the crystalline cohomology of a point. We will see in Subsection 14.4 that the proof of the Hodge-Tate comparison isomorphism for a crystalline prism naturally passes through crystalline cohomology.
One potentially confusing point is that unlike de Rham cohomology in characteristic 0, the crystalline cohomology of a higher-dimensional affine space is not the same as that of a point! In fact, the crystalline cohomology of is computed by the complex where (this ring already admits divided powers on by Example 14.2.2); taking the derived base change from to yields whose cohomology we already know is quite large (Lemma 14.1.6). What Proposition 14.2.6 tells us is that the answer does not change if we include some extra “divided power variables”; see Proposition 14.2.8 for a concrete statement.
In any case, none of this has much meaning without an actual definition of crystalline cohomology itself. For that, see [15].
Proposition 14.2.8. Crystalline and de Rham cohomology of affine space.
Put and let be the -adic completion of the divided power envelope of Then there is a natural quasi-isomorphism
and hence a quasi-isomorphism
Proof.
By repeated application of Proposition 14.2.6 we may reduce to the case in which case this is evident.
Subsection 14.3 Divided powers in -rings
We next make a crucial link between -rings and divided powers.
Remark 14.3.1.
If is a -algebra which admits a -ring structure, then admits divided powers on some ideal if and only if for all See Exercise 2.5.10.
Lemma 14.3.2.
Proof.
Let be the divided power envelope; it is the smallest subring of containing and for all The maximal ideal on which admits divided powers includes both (by construction) and (by Example 14.2.2), and hence also consequently, for all
Hence induces an endomorphism of
We next check that induces a Frobenius lift on this amounts to checking that for all
Corollary 14.3.3.
In Lemma 14.3.2, the divided power envelope equals or more precisely the quotient of by the -ideal generated by
Proof.
Let be the divided power envelope and put there is a natural map which one checks is injective. Within we then have by Lemma 14.3.2 and by Remark 14.3.1. (Compare [25], Lemma 2.36.)
Corollary 14.3.4.
Let be -torsion-free. Choose which form a regular sequence in and set Then the divided power envelope of is a -ring, and can be written as (viewing the latter as a subring of ).
Proof.
By induction this reduces to the case in which case we write for In this case, we may deduce the claim from Lemma 14.3.2 and Corollary 14.3.3 by base change. (Compare [25], Corollary 2.38.)
Remark 14.3.5.
Corollary 14.3.4 implies that the subring of is independent of the choice of -structure on as the characterization via the divided power envelope of makes no reference to or By contrast, is not independent of this choice; see [25], Warning 2.40.
Remark 14.3.6.
Lemma 14.3.2 asserts that the divided power envelope of as a ring is also the divided power envelope as a -ring. The corresponding statement for -rings is false: for the free -ring on (over ), the divided power envelope of is not a -subring of The issue here is with the use of Example 14.2.2: the ring does not admit divided powers on for any prime
This then leads to the question of describing the smallest -subring of containing which admits divided powers on We do not know the answer, but as a partial result we note that this ring contains the elements where is a prime, is a positive integer, and is the prime-to- factor of
A related question is whether Remark 14.3.5 admits a -ring analogue. That is, if is -flat and form a regular sequence in for every prime does the minimal -subring of containing which admits divided powers on depend only on the underlying ring structure of and not its -structure?
Subsection 14.4 Prismatic cohomology for a crystalline prism
We next use divided powers to explicitly compute the cohomology of affine space over a crystalline prism. To begin with, we make the construction of weakly final objects of the prismatic site (Proposition 11.6.5) more explicit in some cases of interest.
Lemma 14.4.1.
vanishes in the homotopy category (More precisely, this is witnessed by a homotopy at the level of -cosimplicial modules; see Definition 16.2.5 for the meaning of this statement.)
Proof.
We may reduce to the case of a polynomial ring in finitely many variables by taking colimits. We may further reduce the case using exterior powers. We may further reduce to the case using base change and induction on the number of variables. At this point, we can write down the homotopy explicitly: if we write the -fold tensor product of as then the homotopy carries to taking to for and to 0 for We leave it to the reader to check that is a homotopy for the identity map (Exercise 14.5.2). (Compare [19], Example 2.16.)
Lemma 14.4.2.
Let be the prism and put Let be the classical -completion of Let be the kernel of the map taking to and to for all Write for the classical -completion of Then is a weakly final object of
Proof.
By Exercise 2.5.8, is a -pair. As in the proof of Proposition 11.6.5. we may apply Lemma 11.6.1 to to obtain a weakly final object of To identify the result explicitly, we step through the proof of Lemma 11.6.1. We first take the derived -completion of as this object is -adically separated this is in fact a classical -completion. In addition the result is -torsion-free, so there is no need to iterate the construction. (Compare [18], Lecture VI, Corollary 2.3.)
Remark 14.4.3.
Note that is itself a Čech-Alexander complex, namely the one associated to the covering in the category of -adic formal schemes. In particular, is an isomorphism in by the Čech-Alexander construction in the category of -formal schemes (and even a homotopy equivalence of cosimplicial -algebras, as per Definition 16.2.5).
Corollary 14.4.4.
with the -fold completed tensor product of over Let be the kernel of the morphism in taking to and to for all and write for the classical -completion of Then is quasi-isomorphic to the Čech-Alexander complex
Proof.
By Lemma 14.4.2, is a weakly final object of Now note that is the -fold product of in Hence we are in the setting described in Remark 11.6.7.
Remark 14.4.5.
Note that while is generated by for all is not generated by for all we must also add the generators for
Remark 14.4.6.
With notation as in Lemma 14.4.2 and Corollary 14.4.4, the map on is an isomorphism. By Remark 14.4.3, is a quasi-isomorphism (and a homotopy equivalence), yielding isomorphisms in of the form
By Corollary 14.3.4, the latter coincides with the -completed divided power envelope of (More precisely, these are homotopy equivalences of cosimplicial -algebras; see again Definition 16.2.5.)
Lemma 14.4.8.
Let be the prism and put Let be the weakly final object of given by Lemma 14.4.2. Then the totalization of the double complex displayed in Figure 14.4.9 is quasi-isomorphic to both its first row and its first column via the inclusion maps.
Proof.
We can compute the cohomology of the total complex using the “first” spectral sequence, in which we first compute the cohomology of the columns. In this case, is independent of by Proposition 14.2.8 each column computes the crystalline cohomology of and for this identification each map represents the identity map on cohomology. Hence the horizontal differentials between the columns (which are alternating sums of the induced maps) are represented by
At the next page of the spectral sequence, we end up with the groups in column 0 and zeroes elsewhere. By Corollary 13.3.8, the map from the first column to the totalization is a quasi-isomorphism. (Compare Example 16.2.4 for a similar phenomenon.)
Meanwhile, by Lemma 14.4.1, each row except the first is homotopic to zero. Consequently, by Corollary 13.3.8 again, the natural map from the first row to the totalization is also a quasi-isomorphism. (Compare [19], Theorem 2.12.)
Corollary 14.4.10.
Let be the prism and put Then is quasi-isomorphic to the crystalline cohomology of the affine space in the sense of Remark 14.2.7, i.e., to for
Proof.
By Remark 14.4.6, we obtain a quasi-isomorphism of with the first row of Figure 14.4.9. By Lemma 14.4.8, this is in turn quasi-isomorphic to the left column of Figure 14.4.9. By Proposition 14.2.8, the latter is quasi-isomorphic to for (note that this amounts to the same use of the Poincaré lemma as was needed to compare columns in Lemma 14.4.8).
Remark 14.4.11.
In Corollary 14.4.10, we write instead of to keep track of the fact that prismatic cohomology computes not crystalline cohomology per se, but rather a canonical Frobenius descent of it.
Proposition 14.4.12.
Proof.
By Lemma 14.4.2, we may compute the object using the Čech-Alexander complex associated to the weakly final object as described in Corollary 14.4.4, and then obtain by applying By Remark 14.4.6, the object (or more correctly ) is represented by the top row of the double complex Figure 14.4.9, which by Lemma 14.4.8 is isomorphic in to the first column of the double complex. By Corollary 14.4.10, that column computes the crystalline cohomology of affine space. By applying we obtain an isomorphism
of -dga’s which in degree is the identity map on
To check that is an isomorphism, it will suffice to deduce from (14.5) that corresponds to the Cartier isomorphism; it suffices to do this in degree 1. As in Definition 12.3.1, consider the exact sequence
Viewing the element as representing a class in we find that its image under the Bockstein differential is represented by This is then the image of under and it remains to transfer the answer via (14.5).
This is the image of along the horizontal arrow in Figure 14.4.9. When we reduce mod we get exactly the image of under the Cartier map, proving the claim.
Exercises 14.5 Exercises
1.
Prove Proposition 14.2.6.