The map
\(\phi_{S/R}\) induces a morphism of complexes thanks to
Corollary 14.1.4. To check that this map is a quasi-isomorphism, we form a decomposition
\begin{equation}
\Omega^i_{S/R} = \bigoplus_{e_1,\dots,e_r \in \{0,\dots,p-1\}} \bigoplus_{1 \leq j_1 \lt \cdots \lt j_i \leq r} x_1^{e_1} \cdots x_r^{e_r}
S^{(1)} dx_{j_1} \wedge \cdots \wedge dx_{j_i}.\tag{14.1}
\end{equation}
We obtain a morphism \((\Omega^\bullet_{S/R}, d_{\dR}) \to (\Omega^\bullet_{S^{(1)}/R}, 0)\) of complexes (not respecting the multiplicative structure) taking \(x_1^{e_1} \cdots x_r^{e_r} dx_{j_1} \wedge \cdots \wedge dx_{j_i}\) to \(dx_{j_1} \wedge \cdots \wedge dx_{j_i}\) for
\begin{equation*}
e_j = \begin{cases} p-1 & j \in \{j_1,\dots,j_i\} \\ 0 & j \notin \{j_1,\dots,j_i\} \end{cases}.
\end{equation*}
We must show that the composition of these maps is homotopic to the identity on \(\Omega^\bullet_{S/R}\text{.}\) By proceeding by induction, we may reduce to the case \(r=1\text{.}\) In this case, for \(e_1 = 1,\dots,p-1\text{,}\) \(d_{\dR}\) maps \(x_1^{e_1} S^{(1)}\) to \(x_1^{e_1-1} S^{(1)}\,dx_1\) taking \(x_1^{e_1} f\) to \(e_1 x_1^{e_1-1} f\,dx\text{,}\) and this map is evidently invertible.