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Section 19 Coperfections in mixed characteristic

Reference.

[18], lecture VIII; [25], section 7.
Given a perfect prism (A,I), we apply prismatic cohomology to construct a “canonical coperfection” of a p-complete A/I-algebra. In general this will not be a true ring but rather something derived; only in certain (important) special cases will we end up with a genuine ring. Nonetheless, this construction is quite useful in mixed-characteristic commutative algebra; for instance, it recovers the André flatness lemma, whose earliest proofs [5], [16] depended heavily on the theory of perfectoid spaces. We incur no such dependence here; we make the argument entirely in the world of rings and schemes, with no recourse to nonarchimedean analytic geometry.
From now on, we write ΔR/A and ΔR/A to mean derived prismatic and Hodge-Tate cohomology (which were previously denoted LΔR/A and LΔR/A), as we will have no further use for the underived versions.

Subsection 19.1 Coperfections in characteristic p revisited

To motivate the mixed-characteristic construction, we start by reconstructing the coperfection of an Fp-algebra in a somewhat exotic-looking fashion.

Definition 19.1.1.

Recall that for R an Fp-algebra, we have defined the coperfection of R as the image Rperf of R under the left adjoint of the forgetful functor from perfect Fp-algebras to arbitrary Fp-algebras. Concretely,
Rperf=colim(RϕRϕR).
Now suppose that R is an algebra over a perfect field k of characteristic p. Let R(1)R be the relative Frobenius map (Definition 14.1.2); then the induced map (R(1))perfRperf is an isomorphism. See also Exercise 19.6.2.

Remark 19.1.2.

A fundamental theorem of Kunz (see [117], tag 0EC0) asserts that a noetherian Fp-algebra is regular if and only if its Frobenius map is flat. (As a reminder, if R is a finite type k-algebra for some perfect field k of characteristic p, then R is regular if and only if it is a smooth k-algebra; see [117], tag 00TQ.) Since flatness is preserved by colimits, we see that if R is a noetherian regular Fp-algebra, then RRperf is flat; the converse is also true (see Exercise 19.6.1). For an analogue in mixed characteristic, see Remark 25.5.3.
The following can be seen as another instance of the same phenomenon that gives rise to the vanishing of the cotangent complex for a morphism of perfect rings in characteristic p (as in the proof of Lemma 3.3.5).

Proof.

Since everything is defined using the formalism of nonabelian derived functors (Definition 17.2.1), it suffices to treat the case where R is a polynomial ring over k in finitely many variables. In this case, it will suffice to check that for each i>0,
colim(ΩR/kiϕRΩR/kiϕR)
vanishes. This follows from the fact that Frobenius kills differential forms: in degree 1 we have
ϕR(xdy)=xpd(yp)=pxpyp1dy=0
and similarly in higher degrees.
To get closer to the mixed-characteristic case, let us reformulate in terms of (derived) prismatic cohomology.

Proof.

Again, we formally reduce to the case where R is a polynomial ring in finitely many variables. To deduce this from Proposition 19.1.3, we need to check that the map
griHT(ϕR):griHT(ΔR/A)griHT(ΔR/A)
induced by the Frobenius on ΔR/A conicides with the map ΩR/kiΩR/ki induced by the Frobenius on R via the identification griHT(ΔR/A)ΩR/ki of Proposition 18.1.4 (note that now we have reverted from derived to ordinary prismatic cohomology). By functoriality, it suffices to treat the case R=k[x]; this amounts to a direct calculation in the style of Lemma 12.3.4, which we leave to the reader. (Compare [18], Lecture XIII, Proposition 1.6.)
We make one more change to prepare for the passage to mixed characteristic: we replace the Frobenius action on Hodge-Tate cohomology, which has no analogue in mixed characteristic, with the prismatic Frobenius.

Proof.

Subsection 19.2 The mixed characteristic case

Definition 19.2.1.

Let (A,I) be a perfect prism with slice A. For RRingA derived p-complete, define the prismatic coperfection
ΔR/A,perf=colim(ΔR/AϕRΔR/AϕR)(p,I)Dcomp(A)
using the A-linear structure on the initial term. This corresponds to the perfection in [18], [25].
Define the lens coperfection as
Rlens=ΔR/A,perfALADcomp(R)
(the derived completion being p-adic) using the R-linear structure coming from RΔR/AΔR/A,perfALA (the latter map coming from the identification of ΔR/A with the first term of the colimit defining ΔR/A,perf). This corresponds to the perfectoidization in [18], [25].
By construction, ΔR/A,perf and Rlens are commutative algebra objects in Dcomp(A) and Dcomp(R), respectively. The Frobenius on ΔR/A induces an automorphism of ΔR/A,perf denoted ϕR.

Remark 19.2.2.

The notation Rlens suggests that the lens coperfection of R depends only on R and not on its description as an A-algebra. This will be confirmed by Lemma 19.2.3.

Proof.

By derived Nakayama (Remark 6.6.6), the first statement implies the third. To check the first and second statements, we may reduce to comparing graded pieces of the Hodge-Tate filtration. Using Proposition 18.1.4 to translate the statement in terms of cotangent complexes plus (17.1), we reduce to checking that the derived p-completion of LB/A vanishes. This holds because both rings are lenses; see Exercise 17.5.4.
Let us consider some examples.

Example 19.2.4. Coperfection for a crystalline prism.

Suppose that (A,I) is crystalline, that is, I=(p) and A=W(A). By Corollary 19.1.5, we have
RlensRperf,ΔR/A,perfW(Rperf)
with everything concentrated in degree 0.

Example 19.2.5. Coperfection for a lens.

Let (A,I) be a perfect prism and suppose that RRingA is itself a lens. By Lemma 19.2.6, ΔR/AW(R) concentrated in degree 0. Since Frobenius is already an automorphism on W(R), it follows that ΔR/A,perfW(R) and RlensR, both concentrated in degree 0.

Proof.

Write R=B for some perfect prism (B,J); by Theorem 7.3.5, the map AB promotes uniquely to a morphism of prisms (A,I)(B,J). Now (RB/JB) is an object of (R/A)Δ, so we have a natural map ΔR/AB=W(R). To check that this is an isomorphism, by derived Nakayama (Remark 6.6.6) it suffices to do this after applying ALA; that is, we must check that ΔR/AR. This follows from Lemma 19.2.3.
We are now ready to consider a simple example where the lens coperfection is not concentrated in degree 0, although the verification of this will come later (see Section 26). This should not necessarily be viewed as a bad thing, as the higher cohomology will carry some important geometric information.

Example 19.2.7. The q-torus.

Let (A,I) be the coperfection of (Zp[[q1]],([p]q)), so that A is the classical (p,[p]q)-completion of Zp[qp]. Take R=A[x±](p).
We will see later (see Section 26) that in this example H1(ΔR/A,perf) and H1(Rlens) are both nonzero. This will follow by our later computation of ΔR/A using a q-de Rham complex (compare Example 12.4.3). We will eventually see that ΔR/A,perf is given by the (p,[p]q)-completion of
A[x±pp]γidJA[x±pp]
where
J=(n(qpn1))(p,[p]q)=ker(AZp,qpn1)
and γ is characterized by
γ(xi)=qixi(iZ[p1]).
In particular, (q1)1 in degree 1 is not a coboundary even modulo [p]q.

Subsection 19.3 More properties of coperfection

Proof.

We treat here only the case where R has bounded p-power torsion. See [25] for a broader result that includes the general case of this assertion.
Let (A,I)(B,IB) be a faithfully flat map of perfect prisms. Put S=R^ALB; then S is p-completely flat over R and thus concentrated in degree 0 (because R has bounded p-power torsion). We need to show that Rlens^ALBSlens; by compatibility with filtered colimits, this reduces to showing that ΔR/AALBΔS/B. This follows by comparing the Hodge-Tate filtrations on both sides using Proposition 18.1.4, then using the analogous compatibility for the cotangent complex and its exterior powers (Proposition 17.1.2).
The following can be viewed as a refinement of Exercise 17.5.1.

Proof.

For a given i>0, set Si=SymFpFp[i]. By construction, Hi(Si) is nonzero; moreover, any class of Hi(R) is in the image of Hi(Si) along some map SiR. Hence it suffices to check that Frobenius kills Hi(Si).
For i=1, we may write
S1=FpFp[x]LFp,
from which we read off that H1(S1)(x)/(x2), which is evidently killed by Frobenius.
For i>1, we may write
Si+1=FpSiLFp
to obtain an identification
Hi1(Si+1)Hi1(FpSiLFp)Hi(Si)
that is compatible with Frobenius. By induction on i, we deduce the desired result. (Compare [24], Proposition 11.6.)

Remark 19.3.3.

It is noted in [24], Remark 11.8 that Lemma 19.3.2 admits a generalization which makes no reference to Frobenius or characteristic p: for any simplicial commutative ring R, the multiplication map R×RR induces the zero map on Hi(R) for all i>0.

Proof.

From its construction, ΔR/A,perf/p carries a natural Frobenius endomorphism; by Lemma 19.3.2, its negative cohomology groups must vanish. By applying derived Nakayama (Exercise 6.7.5) to the canonical truncation τ1(ΔR/A,perf), we deduce the claim. (Compare [18], Lecture VIII, Remark 2.5(1) or [25], Lemma 8.4.)

Proof.

Proof.

Let (A,I) be a perfect prism and let R=A/J be a derived p-complete quotent. Since AR is surjective, ΩR/A1=0 and so LR/A[1]Dcomp0(R). This in turn implies that iLR/A[i]Dcomp0(R) for all i, and similarly after derived p-completion. By the Hodge-Tate filtration (Proposition 18.1.4), we deduce that ΔR/ADcomp0(R) and hence ΔR/ADcomp0(A). Now apply Lemma 19.3.5 to deduce that Rlens is concentrated in degree 0, where it is a lens.

Remark 19.3.7.

As indicated in [18], Lecture VIII, Remark 2.5, Lemma 19.3.4 and Lemma 19.3.5 are concrete consequences of the statement that the action of ϕR gives ΔR/A,perf the structure of a “derived perfect δ-ring”. We will not try to unpack this statement further here.

Subsection 19.4 André flatness

We next use prismatic coperfections to construct faithfully flat morphisms of prisms; this recovers an important assertion of mixed-characteristic commutative algebra.

Definition 19.4.1.

A ring R is absolutely integrally closed if every monic polynomial over R has a root. We often abbreviate this to AIC.

Proof.

By [117], tag 0DCS, the localization of R at any prime ideal is strictly henselian; this implies the claim at once.

Proof.

Define the ring
R=A[xp](p)/(P);
by construction, R is a regular semilens and AR is p-completely faithfully flat. By Remark 18.2.3, ΔR/A is concentrated in degree 0, where it is a (p,I)-completely flat A-algebra. By the Hodge-Tate comparison (Proposition 18.1.4), RΔR/A is p-completely faithfully flat.
By Corollary 19.3.6, ΔR/A,perf is concentrated in degree 0, where it is a perfect (p,I)-complete δ-ring which we call B. By the previous paragraph, RΔR/A,perf is p-completely faithfully flat, so (A,I)(B,IB) is faithfully flat. By construction, B is an R-algebra, so it contains a root of P. (Compare [25], Proposition 7.11.)

Proof.

This follows directly from Lemma 19.4.3 via transfinite induction. (Compare [25], Theorem 7.12.)

Proof.

By Corollary 19.3.6, RRlens is the universal map from R to a lens, which we wish to show is surjective. Since we may check this after a p-completely faithfully flat base extension, using Theorem 19.4.4 we may reduce to the case where the multiplicative map :AA is surjective. Let J be the kernel of AR. We can then choose elements xiA for i running over some index set I such that the elements xiA form a set of generators of J, and check directly that the quotient R of A by the p-completion of the ideal generated by xipj for all iI,j0 is a lens. The natural map RR satisfies the same universal property as RRlens, so RlensR is indeed a quotient of R. (Compare [18], Corollary 3.2.)

Remark 19.4.7.

In the theory of perfectoid spaces, the surjectivity assertion in Corollary 19.4.6 corresponds to the fact there is no difference between Zariski closed subsets and strongly Zariski closed subsets of a perfectoid space. These concepts had previously been distinguished in [108], Remark II.2.4.

Subsection 19.5 Examples of lens coperfection

We have the following analogue of Example 3.4.3.

Example 19.5.2.

Let R be a lens and let S be the regular semilens R[xp](p)/(x). Then SlensR with the kernel of SSlens being the closure of the ideal (xp). We check this from the adjunction property (Corollary 19.3.6): if ST is a morphism with T a lens, then T is reduced (Corollary 8.4.7) and so xpnker(ST) for all n.
In this case, it is easy to see that the kernel of SSlens is strictly larger than the radical of the ideal x. For example, if R is p-torsion-free, then the element
n=1pnxpn
belongs to the kernel but no power of it is divisible by x.

Example 19.5.3.

Let R be a completed algebraic integral closure of Zp and let S be the regular semilens R[xp](p)/(x1). Fix a coherent sequence (ζpn) of p-power roots of unity in R. Then Slens can be described as the ring of continuous functions ZpR, viewed as a subring of the product cZpR, via the map taking xpn to (ζpnc)cZp. As in Example 19.5.2, this can be checked using the adjunction property of lens coperfection (Corollary 19.3.6).
The kernel of the map SSlens has been analyzed in [53]: it is the radical of the ideal (x1), but is strictly larger than (x1) itself. However, it is difficult to exhibit “explicit” elements witnessing the difference between the two ideals.
Here is a variation of the previous example.

Example 19.5.4.

Let R be a p-torsion-free lens and let S be the nonregular semilens R[xp,yp](p)/(xpnypn:n=0,1,). In this case, SlensR[xp](p) via the map ypnxpn. By contrast, if we take the quotient of R[xp,yp](p) by the ideal (xy), we end up with something more similar to Example 19.5.3 (particularly if R contains a coherent p-power sequence of roots of unity).
Note that in the previous examples, the complications all arise from the kernel of the map to the lens coperfection. If we exclude this by requiring the semilens to be p-torsion-free, then one can express the lens coperfection in more classical language. (One can also make some statements in the more general case, for which we defer to [70] for details.)

Definition 19.5.5.

For R a p-torsion-free ring, the p-root closure (or p-normalization) of R is the minimal subring S of R[p1] containing R and closed under taking p-th roots. That is, if xR[p1] and xpS, then also xS.

Proof.

It is clear that every x of this form belongs to the p-root closure. It thus suffices to check that the resulting set is a ring, as then it is clear that it contains R and is closed under taking p-th roots. We leave the verification to the reader; alternatively, see [105] where the concept of the p-root closure was first considered in detail.

Proof.

Exercises 19.6 Exercises

1.

Show that for RRingFp, the Frobenius map ϕR:RR is flat if and only if the canonical map from R to its coperfection Rperf is flat.
Hint.
Let R1 be a copy of R viewed as an R-algebra via ϕ. The map R1Rperf induces a surjection on spectra; hence if I is a finitely generated ideal of R and
0KIRR1IR1R1/IR10
is exact with K0, then IRperfIRperf is not injective either. This checks a standard criterion for flatness ([117], tag 00M5).

2.

Let RS be a morphism of Fp-algebras such that the corresponding map SpecSSpecR is a universal homeomorphism. Show that the induced map RperfSperf of coperfections is an isomorphism.