Since we already know from
Definition 7.3.5 that
\(v\) factors through
\(C_\QQ\) and surjects onto
\(\widehat{\ZZ}\text{,}\) it suffices to check that for every number field
\(K\text{,}\) \(v(\Norm_{K/\QQ} I_K) = f_{K/\QQ} \widehat{\ZZ}\text{.}\) We may establish this by checking that the map
\begin{equation*}
I_K \stackrel{\Norm_{K/\QQ}}{\to} I_\QQ \to \Gal(\QQ^{\cyc}/\QQ)
\end{equation*}
has image
\(\Gal(K^{\cyc}/K) \subseteq \Gal(\QQ^{\cyc}/\QQ)\text{,}\) as then we get the desired condition by projecting from
\(\Gal(\QQ^{\cyc}/\QQ)\) to
\(\Gal(\QQ^{\smcy}/\QQ)\text{.}\) Note that for
\(K = \QQ\text{,}\) this follows from Artin reciprocity for cyclotomic extensions (
Definition 1.1.7).
In one direction, the fact that
\(I_K\) maps into
\(\Gal(K^{\cyc}/K)\) is a corollary of local reciprocity (
Theorem 4.1.2) plus Artin reciprocity for cyclotomic extensions as used above.
In the other direction, the same logic shows that for each positive integer
\(n\text{,}\) the image of
\(I_K\) in
\(\Gal(K(\zeta_n)/K)\) equals the image of the classical Artin map for
\(K(\zeta_n)/K\text{;}\) it will thus suffice to check that these maps are surjective. It is convenient to deduce this from the First Inequality; see
Proposition 7.3.7 below.